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# Camera position in space (OpenGL)

Generally there's no such thing as "**camera position**" in OpenGL, basically you start at point 0,0,0 looking down negative z-axis. (X-axis goes right, Y-axis goes up).

To see the world from (1,0,0), which is 1 unit right on x axis, you should move the camera right 1 unit, but you can't, because there is no such thing as "camera" position, so you have to "move" the whole WORLD 1 unit left.

This is done due to the fact, that world drawing process is simply matrix multiplication. The point in space is multiplied by projection matrix, by modelview matrix and then converted to screen space. So, in order to "see" the world from 1 unit RIGHT, you have to modify**modelview** matrix so that it would move every pixel 1 unit LEFT.

## Finding world coordinates of camera

Use gluUnProject call with center of viewport and 0 as z-coordinate to find real-world center of the camera.

**viewport** is viewport matrix (See "Reading").

## Camera direction

Finding "where" the camera looks is basically the same - use gluUnProject with center of viewport and 1.0 (instead of 0.0) as z-coordinate and use vector subtraction with the camera center (previous paragraph) to find the vector of where the camera is looking.

**Another approach** would be extracting back vector from modelview matrix and inverting it.

Generally there's no such thing as "

To see the world from (1,0,0), which is 1 unit right on x axis, you should move the camera right 1 unit, but you can't, because there is no such thing as "camera" position, so you have to "move" the whole WORLD 1 unit left.

This is done due to the fact, that world drawing process is simply matrix multiplication. The point in space is multiplied by projection matrix, by modelview matrix and then converted to screen space. So, in order to "see" the world from 1 unit RIGHT, you have to modify

gluUnProject( (viewport[2]-viewport[0])/2 , (viewport[3]-viewport[1])/2, 0.0, model, proj, view, &cx,&cy,&cz )cx,cy,cz would be the center of image plane,

gluUnProject( (viewport[2]-viewport[0])/2 , (viewport[3]-viewport[1])/2, 1.0, model, proj, view, &cx1,&cy1,&cz1 )The vector (cx1-cx, cy1-cy, cz1-cz) would be the camera direction. Where cx,cy,cz is camera center (see "Finding world coordinates of camera" above).